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如何赢得荆棘之兴与大发明家的对抗赛荆棘之兴 is in the s tier of champions

荆棘之兴 vs 大发明家

如何在LoL中以荆棘之兴的身份击败大发明家荆棘之兴 is in the b tier of champions
MageSupport
MageSupport

如何击败大发明家成为荆棘之兴

based on 2,558 荆棘之兴 vs 大发明家 matchups
胜率
52.4 %
kda
2.37
受欢迎度
1.6 %

How We Analyze LoL Champion Counters

We calculate our counter stats from the millions of ranked League of Legends games that we evaluate each and every week. This guide on how to beat 大发明家 as 荆棘之兴 resulted from an analysis of 2558 ranked matches where both champs clashed against one another. This particular counter matchup is fairly rare. 荆棘之兴 fights 大发明家 in only 1.6% of her matches.

荆棘之兴 vs 大发明家 Matchup Summary

荆棘之兴 has done a good job of countering 大发明家. Typically, she wins a terrific 52.4% of games the champions face each other in. In 荆棘之兴 versus 大发明家 games, 荆棘之兴’s team is 0.1% more likely to earn first blood, indicating that she most likely will get first blood against 大发明家.

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物品

第一项

期望时间
生命药水云游图鉴

下一个项目

5分钟
增幅典籍荧尘

Core 荆棘之兴 Items

22分钟
瑞莱的冰晶节杖残疫扎兹沙克的溃口

可选项目

蜕生兰德里的折磨风暴狂涌卢登的伙伴

Summoner Spells

summonerflash summoner spell D
summonerdot summoner spell F

技能顺序

为荆棘之兴提升等级的第一个技能e
>
为荆棘之兴提供的第二种能力,以提高水平q
>
荆棘之兴 最大化的最后一项技能w

符文

巫术奥术彗星法力流系带超然焦灼
主宰血之滋味无情猎手
Adaptive ForceAdaptive ForceArmor
荆棘之兴's passive ability p
荆棘之兴's q ability q
荆棘之兴's w ability w
荆棘之兴's e ability e
荆棘之兴's ultimate ability r
1
E
2
W
3
Q
4
E
5
E
6
R
7
E
8
Q
9
E
10
Q
11
R
12
Q
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Q
14
W
15
W
16
R

Guide to Countering 大发明家 as 荆棘之兴

Tips for Playing as 荆棘之兴 against 大发明家

- 种子可以为你的队伍提供视野,请好好利用。

- 在你的技能施放之后,再往你的技能路径上播下种子,可以确保你的种子能够百分百变成植物。

- 婕拉是一个出色的伏击手——寻找时机,然后在草丛里布下陷阱,再诱引敌人进来。

Advice to Win Against 大发明家

- 要当心黑默丁格的终极技能,因为他能用终极技能来化解当前他所遇到的大部分麻烦。一旦他交出终极技能,就可以准备击杀他了!

- 黑默丁格召唤炮塔后,尽快伙同你的队友摧毁炮塔。炮塔聚集在一起后会变得很强力。

荆棘之兴 vs 大发明家 Counter Stats

荆棘之兴 Image
winRate
52.4 %
VS
winRate
47.6 %
大发明家 Image
3.8
< kills >
4.7
6
< deaths >
6.5
10.4
< assists >
6.9
0.82
< killingSprees >
1.05
61
< cs >
136
0.11
< dragons >
0.16
0.45
< inhibitors >
0.47
937
< physicalDamage >
756
19,453
< magicDamage >
23,410
1,035
< trueDamage >
699
21,425
< damageDealt >
24,866
19,307
< damageTaken >
21,490
9,885
< goldEarned >
11,122
1.7
< towers >
1.89
0.03
< barons >
0.05
2,269
< heal >
2,328
11,984
< xp >
14,105
56
< visionScore >
29
24
< wardsPlaced >
14
307
< ccTime >
277

How to Counter 大发明家 with 荆棘之兴 in LoL

The stat comparisons provided here show several important 荆棘之兴 against 大发明家 matchup stats that may help you figure out the differences and similarities between this set of champs. For instance, 荆棘之兴’s KDA ratio ([kills + assists] / deaths) of NaN is better than 大发明家’s ratio of NaN, demonstrating that 荆棘之兴 may be more central to her team's team fighting potential than 大发明家..

荆棘之兴 normally has a similar longest killing spree as her counter does. Commonly, she receives a similar amount of damage to 大发明家. This is usually reflective of different amounts of tankyness; however, it can also illustrate that the one champ has less mobility and thus is not able to kite away from additional damage when poked or engaged.

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伤害数据

荆棘之兴
大发明家
物理伤害
魔法伤害
真实伤害

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荆棘之兴
大发明家

championDifferences.whoIsBetter

Both League of Legends champions are great. Both champs have their strengths, weaknesses, and counters. In League's current meta, 荆棘之兴 usually wins when facing off against 大发明家, with a 52.4% win rate. As a result, 荆棘之兴 makes a good counter for 大发明家.

While 荆棘之兴 does have a higher win rate compared to 大发明家, when they face off with one another, 荆棘之兴 also has a lower learning curve that makes her a less time consuming champ to learn. You should be be fine when picking 荆棘之兴 into 大发明家as her relative depth means you may not be able to reach her full potential without a significant amount of practice beforehand.

Additionally, 荆棘之兴 has some amount of CC and other utility, a similar amount to 大发明家. This makes her just as valuable during team fights, especially when trying to counter champions with a lot of burst damage.

While there isn't one best champion overall in League of Legends, in 荆棘之兴 vs 大发明家 matchups, 荆棘之兴 is the better champion with a noticably higher win rate, less champion complexity, and a similar amount of utility to help out your team members during late stage team fights.

荆棘之兴 is an above average counter to 大发明家. Focus your play on increasing your CS and clearing objectives. If you can do that, you should be able to stand on your own as 荆棘之兴 against 大发明家.

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To learn all of the intricacies of 荆棘之兴 to counter 大发明家 during both the laning and mid / late game phases of League of Legends, you should continue reading to pick up a few extra tricks and insights into this matchup. If you listen to the build and tips displayed above, you will grow your win rate by a lot and be that much closer to League of Legends pro players.

荆棘之兴 typically picks up less CS compared to 大发明家. Champs who on average don't take many minion kills typically don't need much CS to be valuable teammates, such as support champions. They are capable of scaling well off of their skills, stats, and first items alone. Yet, champs with large amounts of CS, such as hyper-carries, usually require several high cost items to be effective. In either situation, try to do better than the numbers displayed on this page to do well.

The best items to focus on in your 荆棘之兴 versus 大发明家 build include 瑞莱的冰晶节杖, 残疫, and 扎兹沙克的溃口. When 荆棘之兴 incorporated at least these three pieces in her build, she performed a lot better countering 大发明家 than with many other common item sets. In fact, 荆棘之兴 boasted an average win rate of 52.4% battling 大发明家 with these items in her kit.

To have the best probability of crushing 大发明家 as 荆棘之兴, 荆棘之兴 players should take the 奥术彗星, 法力流系带, 超然, 焦灼, 无情猎手, and 血之滋味 runes from the 巫术 and 主宰 rune sets. Out of all the rune combinations players used for 荆棘之兴 vs 大发明家 fights, this mix of runes resulted in the highest win rate. Notably, these runes provided a 52.4% winrate overall.

By default, tips, statistics, and builds on how to beat 大发明家 as 荆棘之兴 are shown for all ranked divisions. If you want to filter the statistics and builds to a distinct skill level, you should use the selection menu earlier on the page.